6x^2+110x-3000=0

Solution for 6x^2+110x-3000=0 equation:

6x^2+110x-3000=0

a = 6; b = 110; c = -3000;
Δ = b2-4ac
Δ = 1102-4·6·(-3000)
Δ = 84100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{84100}=290$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-290}{2*6}=\frac{-400}{12}
=-33+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+290}{2*6}=\frac{180}{12}
=15
$